Inner automorphisms of an alternating group

Let A5 denote the alternating group on a 5-element set {1,2,3,4,5}. The set of automorphisms of A5 form a group, denoted Aut(A5). The group of conjugations of A5, denoted Conj(A5), is the subgroup of Aut(A5) consisting of automorphisms of the form γs:=s()s1 where sA5. Explicitly, γs(x)=sxs1 for any xA5.

  1. Prove that the function γ:A5Conj(A5), taking sA5 to γs, is a surjective homomorphism.
  2. Prove that A5 is isomorphic to Conj(A5).